Respuesta :

calculista

Answer:

[tex]528[/tex]

Step-by-step explanation:

we have

[tex]2(3x^{3} +2y^{2})[/tex]

For [tex]x=-2, y=12[/tex]

substitute the value of x and the value of y in the expression

[tex]2(3(-2^{3}) +2(12^{2}))[/tex]

[tex]2(3(-8) +2(144))[/tex]

[tex]2(-24 +288)[/tex]

[tex]2(264)[/tex]

[tex]528[/tex]

imlittlestar

Answer:

The value of expression 2(3x^3 + 2y^2) when x = -2 and y = 12 is 528

Step-by-step explanation:

To find the value of 2(3x^3 + 2y^2)

The expression is 2(3x^3+2y^2)

x = -2 and y = 12

Substitute the value of x and y in the above expression we get,

2[3(-2)^3 +2(12)^2] =  2[ (3 * (-8) ) + (2*144)]

= 2[-24 + 288] = 2 * 264 = 528

Therefore the value of expression 2(3x^3 + 2y^2) when x = -2 and y = 12 is 528

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