Answer:
doubles
Explanation:
The relationship between angular speed and linear speed in case of a circular motion is the following:
[tex]v=\omega r[/tex]
where
v is the linear speed
[tex]\omega[/tex] is the angular speed
r is the distance from the centre of the circular path
In this proble, the pet hamster moves to a point twice as far from the center; this means that its distance from the centre, r', is doubled:
[tex]r'=2r[/tex]
While the angular speed [tex]\omega[/tex] remains the same. Therefore, the new linear speed is
[tex]v'=\omega r' = \omega (2r)=2 \omega r=2v[/tex]
So, the correct answer is
the linear speed doubles
