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Line p contains point (6, -5) and is perpendicular to line q. The equation for line q is y = 3x + 5. 1) Write an equation for line p

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MrsStrong

Answer:

[tex]y = -\frac{1}{3}x -3[/tex]

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes. To find the line, convert the slope of q and substitute it with (6, -5) into point slope form.

y = 3x + 5 is q. It has a slope of 3. So p will have a slope of -1/3.

[tex]y - y_1 = m(x-x_1)\\y - -5 = -\frac{1}{3}(x - 6)\\y + 5 = -\frac{1}{3}x + 2\\y = -\frac{1}{3}x -3[/tex]

Answer:

y = -1/3x -3

Step-by-step explanation:

Lines

Perpendicular lines have negative reciprocal slopes. To find the line, convert the slope of q and substitute it with (6, -5) into point-slope form.

y = 3x + 5 is q. It has a slope of 3. So, p will have a slope of -1/3.

y - y1 = m ( x - x1)

y - (-5) = -1/3 ( x - 6)

y + 5 = - 1/3x + 2

y = -1/3x - 3

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