Respuesta :
Answer: x=- 8 or x=2
Step-by-step explanation:
1. To solve this problem you can applly the quadratic formula, which is shown below:
[tex]x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}[/tex]
2. The quadratic equation is:
[tex]x^{2}+6x-6-10=0\\x^{2}+6x-16=0[/tex]
3. Then:
a=1
b=6
c=-16
4. Therefore, when you substitute these values into the quadratic formula, you obtain the following result:
[tex]x=\frac{6+/-\sqrt{6^{2}-4(1)(-16)}}{2(1)}[/tex]
[tex]x_1=-8\\x_2=2[/tex]
Answer:
x = -8 or x = 2
Step-by-Step Explanation:
Given equation is :
x²+6x-6 = 10
Adding -10 to both sides of above equation,we get
x²+6x-6-10 = -10+10
x²+6x-16 = 0
We can solve above equation by factoring.
Split the middle term of above equation so that the sum of two terms should be 6 and their product be -16.
x²+8x-2x-16 = 0
Make two groups and taking common
x(x+8)-2(x+8) = 0
Taking (x+8) common,we get
(x+8)(x-2) = 0
Applying zero-Product Property to above equation,we get
x+8 = 0 or x-2 = 0
x = -8 or x = 2 which is the answer.