Answer:
[tex]x=\frac{7 +/-\sqrt{229} }{10}[/tex]
Step-by-step explanation:
To solve the quadratic, use inverse operations to set it equal to 0.
[tex]-5x^2+7x=-9\\-5x^2+7x+9=0[/tex]
To solve, use the quadratic formula and substitute a= -5, b= 7 and c= 9.
[tex]x=\frac{-b +/-\sqrt{b^2-4ac} }{2a} \\\\x=\frac{-7 +/-\sqrt{7^2-4(-5)(9)} }{2(-5)} \\\\x=\frac{-7 +/-\sqrt{49+180} }{-10} \\\\x=\frac{7 +/-\sqrt{229} }{10}[/tex]
