Answer: [tex]\bold{\dfrac{5}{12}}[/tex]
Step-by-step explanation:
greater than 3 means the sum is either 4, 5, or 6.
There are 15 permutations that meet the criteria:
(1, 3), (1, 4), (1, 5), (1,6)
(2, 2), (2, 3), (2, 4), (2, 5), (2,6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3,6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4,6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5,6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6,6)
There are 6²= 36 total permutations for 2 dice.
[tex]Probability=\dfrac{\#\ of\ permutations> 3}{total\ \#\ of\ permutations}\\\\.\qquad \qquad =\dfrac{15}{36}\\\\.\qquad \qquad =\dfrac{5}{12}\\\\[/tex]
