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A shopper in a supermarket pushes a cart with a force of 35 N directed at an angle of 25 degrees downward from the horizontal. Find the work done by the shopper on the cart as the shopper moves along a 50 m length of aisle.

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TarinaLeal

So:

F = 35 N

α = 25 °

d = 50 m

Knowing that W = F.d.cosα

Then: W = 35 × 50 × cos25°

⇔ W = 1586 J

Cricetus

The work done by shopper is "1.586 KJ"

Given values are:

Force,

  • F = 35 N

Angle,

  • [tex]\Theta[/tex] = 25°

Distance,

  • d = 5 m

The work done will be:

→ [tex]W = Fd Cos\Theta[/tex]

By putting the values, we get

→      [tex]= 35\times 50\times Cos(25^{\circ})[/tex]

→      [tex]= 1586 \ J[/tex]

or,

→      [tex]= 1.586 \ KJ[/tex]

Thus above answer is right.

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https://brainly.com/question/20123612

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