Answer:
235 yd²
Step-by-step explanation:
It is convenient to divide the figure into 2 or 3 parts. One is the trapezoid above the dotted line, with parallel bases of length 20 and 35 and height 6. Its area is ...
A = (1/2)(b1 +b2)h = (1/2)(20 +35)·6 = 165 . . . . yd²
Then the remaining two triangles can be rearranged to form a rectangle 10 yards by 7 yards. Its area is the product of those dimensions:
A = L·W = (10 yd)(7 yd) = 70 yd²
The area of the entire figure is the sum of these areas, ...
trapezoid area + rectangle area = 165 yd² +70 yd² = 235 yd²
