Answer:
[tex]4x^4\sqrt[3]{2x^2}[/tex]
Step-by-step explanation:
The radical on the right is the cube root of a perfect cube, so simplifies easily. The radical on the left has a cubic factor of x that can be brought out. You have ...
[tex]\sqrt[3]{2x^5}\cdot\sqrt[3]{64x^9}=\sqrt[3]{x^3\cdot 2x^2}\cdot\sqrt[3]{(4x^3)^3}\\\\=x\sqrt[3]{2x^2}\cdot 4x^3=4x^4\sqrt[3]{2x^2}[/tex]
