The volume of hcl gas required to react with excess ca to produce 11.4 l of hydrogen gas at 1.62 atm and 62.0 °c is ________ l.

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Answer:

22.8 L  

Step-by-step explanation:

We can use Gay-Lussac's Law of Combining Volumes to solve this problem:

Gases at the same temperature and pressure react in simple whole-number ratios.

1. Write the chemical equation.

Ratio:                 2 L                             1 L

          Ca(s) + 2HCl(g) ⟶ CaCl₂(s) + H₂(g)

V/L:                                                     11.4

2. Calculate the volume of HCl.

According to the law, 2 L of HCl form 1 L of H₂.

Then, the conversion factor is (2 L HCl/1 L H₂).

Volume of HCl = 11.4 L H₂ × (2 L HCl/1 L H₂)

                         = 22.8 L HCl

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