AsiaLeigh
contestada

A 20-foot ladder is leaned against a wall. If the base of the ladder is 8 feet from the wall, how high up on the wall will the ladder reach? Round the answer to the nearest tenth.

A. 21.5
B. 18.3
C. 15.7
D. 19.1

I keep getting 18.3 as my answer, but I feel like I'm doing something wrong. Can somebody please explain and show me how to do this correctly? I don't think I'm doing it right :(

Respuesta :

sjenkins416
You use Pythagorean theorem to solve it and you get 18.3. Just look at the picture to see how i solved it
Ver imagen sjenkins416
ashishdwivedilVT

The maximum possible Height of the ladder is 18.3 ft.

What is Pythagoras Theorem?

The Pythagoras theorem states that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Here, let the height of ladder (Perpendicular) be x ft.

          Length of ladder (Hypotenuse) = 20 ft

          Distance from wall (Base) = 8 ft.

By Pythagoras theorem,

    H² = P² + B²

    (20)² = P² + 8²

    400 = P² + 64

     P² = 400 - 64

     P² = 336

     P =√336

    P = 18.3 ft

Thus, the maximum possible Height of the ladder is 18.3 ft.

Learn more about Pythagoras Theorem from:

https://brainly.com/question/343682

#SPJ2

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