Answer with explanation:
If a line is drawn parallel to one side of triangle, then it divides the other two sides in the same ratio.
KM ║JN
[tex]\frac{JK}{KL}=\frac{NM}{ML}[/tex]
So, Solving for, x
[tex](x-5)(x+4)=x(x-3)\\\\ x(x+4)-5(x+4)=x\times x - 3 x\\\\ x^2+4 x -5 x -20=x^2 - 3 x}\\\\ -x-20= -3 x\\\\ -x + 3 x=20\\\\ 2 x=20\\\\x=\frac{20}{2}\\\\ x=10[/tex]
