Christina wants to compute the cost of tiling the floor in her bathroom. The floor measures 7 feet 6 inches by 8 feet 10 inches. Each tile covers 1 square foot. —A box of 45 tiles costs $35.95.

(Christina is buying 2 boxes)

What is the cost of the tile needed for this project?



I got an answer of $71.9. Is that correct?

Respuesta :

frika

Answer:

Two boxes will cost [tex]\$35.95\cdot 2=\$71.9.[/tex] The cost of one tile is approximately [tex]\dfrac{\$71.9}{67}\approx \$1.08.[/tex]

Step-by-step explanation:

Note that 1 ft = 12 in, then

[tex]7\ ft\ 6\ in=7\cdot 12+6\ in =90\ in,\\ \\8\ ft\ 10\ in=8\cdot 12+10\ in=106\ in.[/tex]

The area of the floor is

[tex]90\cdot 106=9540\ in^2.[/tex]

Now

[tex]1\ ft^2=144\ in^2,[/tex]

then

144 sq. in - 1 tile,

9540 sq. in - x tiles.

Mathematically,

[tex]\dfrac{144}{9540}=\dfrac{1}{x},\\ \\x=\dfrac{9540}{144}=66.25[/tex]

tiles is needed to cover the floor (67 full tiles).

Each box of tiles contains 45 tiles, so Cristina has to buy 2 boxes. These two boxes will cost [tex]\$35.95\cdot 2=\$71.9.[/tex] The cost of one tile is approximately [tex]\dfrac{\$71.9}{67}\approx \$1.08.[/tex]

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