Answer:
[tex]y=0.32^{x}[/tex]
Step-by-step explanation:
Whenever we see any exponential function, for the first point, remember this simple rule: every exponential function [tex]a^{x}[/tex] always returns [tex]a[/tex] when evaluated at [tex]x=1[/tex] . In fact, [tex]a^{1}=a[/tex] for every possible base [tex]a[/tex] .
So, we can see that the graph of the exponential passes through the point [tex](1,y)[/tex] where [tex]y[/tex] appears to be between 0 and 1 and also if we look closely in the figure the y line seems to be more near to 0 rather than 1. So, the only feasible option would be (d) i.e [tex]y=0.32^{x}[/tex], because it passes through the point [tex](1,0.32)[/tex].
For other option (b) [tex]y[/tex] value must be in between 2 and 3 for [tex]x=1.[/tex]
For option (c) [tex]y[/tex] value must be in between 3 and 4 for [tex]x=1.[/tex]
which is not the case, so option d is correct.
