Respuesta :
Answer:
1. 5/2x^3 - 3x^2 - 8x + 8.
2. 9.82, -0.82 (to the nearest hundredth).
Step-by-step explanation:
1. (1/2x - 1)(5x^2 + 4x - 8)
= 1/2x(5x^2 + 4x - 8) - 1 (5x^2 + 4x - 8)
= 5/2x^3 + 2x^2 - 4x - 5x^2 - 4x + 8
= 5/2x^3 - 3x^2 - 8x + 8.
2. 4x^2 - 36x - 32 = 0
4(x^2 - 9x - 8) = 0
x = [ -(-9) +/- √ (-9)^2 - 4 * 1 * -8) ] / 2
= 9/ 2 +/- √(113)/2
= 9.82, -0.82. (answer)
Answer: x = 1; x = 8
Step-by-step explanation:
This is late but I suppose it'll come to use later for some other k12 kid. For the second problem, you'll wanna divide everything by 4 first just to make things easier.
4x^2 / 4 -36x/4 32/4 = 0/4
This would equal to: x^4 - 9 + 8 = 0
Then, find two numbers that multiply to make 8, but add to make -9. (If that makes sense...forgot the name of the rule.)
List the factors of 8 and see what you're working with.
1, 8
-1, -8
2, 4
-2, -4
-1 and -8 multiply to make 8 and add to make -9. (-1 - 8 = -9); (-1 * -8 = 8)
Now we can plug this into the equation. (x - 1) (x - 8) = 0
So, x - 1 = 0 and x - 8 = 0
Now simplify: x = 1; x = 8