Answer:
[tex]\large\boxed{y=\dfrac{2}{3}x+\dfrac{1}{3}\qquad\text{slope-intercept form}}\\\\\boxed{y-1=\dfrac{2}{3}x-\dfrac{2}{3}\qquad\text{point-slope form}}\\\\\boxed{2x-3y=-1\qquad\text{standard form}}[/tex]
Step-by-step explanation:
[tex]\text{The standard form:}\ Ax+By=C[/tex]
[tex]\text{The point-slope form:}\\\\y-y_1=m(x-x_1)\\\\m-slope\\\\\text{We have the slope}\ m=\dfrac{2}{3}\ \text{and the point}\ (1,\ 1).\ \text{Substitute:}\\\\\underline{y-1=\dfrac{2}{3}(x-1)}\qquad\text{use the distributive property}\\\\y-1=\dfrac{2}{3}x-\dfrac{2}{3}\qquad\text{add 1 to both sides}\\\\\underline{y=\dfrac{2}{3}x+\dfrac{1}{3}}[/tex]
[tex]y=\dfrac{2}{3}x+\dfrac{1}{3}\qquad\text{multiply both sides by 3}\\\\3y=2x+1\qquad\text{subtract 2x from both sides}\\\\-2x+3y=1\qquad\text{change the signs}\\\\\underline{2x-3y=-1}[/tex]
