Respuesta :
Answer:
The factor form of given polynomial is (7xy+2)(2x-1). The required factor is (7xy+2).
Step-by-step explanation:
The given polynomial is
[tex]14x^2y+4x-7xy-2[/tex]
Factor out the common factors from first two terms and last two terms.
[tex]2x(7xy+2)-1(7xy+2)[/tex]
Now, take out common factor (7xy+2).
[tex](7xy+2)(2x-1)[/tex]
The factor form of given polynomial is (7xy+2)(2x-1).
Therefore the required factor is (7xy+2).
Answer:
Answer is (7xy+2)
Step-by-step explanation:
We shall use grouping method to solve the factor of given expression
[tex]14x^2y+4x-7xy -2 \\2x(7xy+2)-1(7xy +2)\\(2x-1) (7xy+2)[/tex]
In first step we make two group by taking first two terms together
and then taking next two terms together
in first two terms we take 2x as common factors which leave 7xy as first and 2 as second term
likewise we can take -1 common in last two terms and we have again 7xy and 2
now from both expression we get 7xy+2 as common and we get
(7xy+2) (2x-1) as factor
one factor is given in the solution another factor is (7xy+2)
