Answer:
35.6 s
Explanation:
The power through the resistor is given by:
[tex]P=VI[/tex]
where V=9.0 V is the voltage and I=0.50 A is the current. Substituting into the formula, we find
[tex]P=(9.0 V)(0.5 A)=4.5 W[/tex]
The power is also equal to:
[tex]P=\frac{W}{t}[/tex]
where W is the work done while t is the time taken. Since we know the work done, W=160 J, we can re-arrange the equation to find the time taken:
[tex]t=\frac{W}{P}=\frac{160 J}{4.5 W}=35.6 s[/tex]
The work of 160 J is to be done while separating the charges across the circuit for the time interval of 35.55 s.
The battery should be connected for 35.55 seconds.
Given that the voltage of the battery V is 9.0 V and the current I flowing throw the resistor is 0.50 A.
The power across the resistor can be calculated as given below.
[tex]P = VI[/tex]
Substituting the values,
[tex]P = 9 \times 0.50[/tex]
[tex]P = 4.5\;\rm Watt[/tex]
Power can be defined as is the rate at which that work is done. This can be written as,
[tex]P = \dfrac {W}{t}[/tex]
Where W is the work done and t is the time. Given that the work done is 160 J while separating charges.
[tex]4.5 = \dfrac {160}{t}[/tex]
[tex]t = 35.55\;\rm s[/tex]
Hence we can conclude that for 35.55 seconds, the battery should be connected to the circuit to do the work of 160 J while separating the charges.
To know more about the work and power, follow the link given below.
https://brainly.com/question/526992.
