Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball on her second try than her first? Express your answer in feet and inches A. 9 ft 1/2 in. B. 28 ft 1/2 in. C. 28 ft 6 in. D. 126 ft.

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ApusApus ApusApus · Answer 1 · 2019-02-15T16:07:17+01:00

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and [tex]51\frac{1}{3}[/tex] yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from [tex]51\frac{1}{3}[/tex] yards.

[tex]\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}[/tex]

[tex]\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}[/tex]

Let us have a common denominator.

[tex]\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}[/tex]

[tex]\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}[/tex]

[tex]\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}[/tex]

[tex]\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}[/tex]

[tex]\text{1 yard}=3\text{ feet}[/tex]

[tex]\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}[/tex]

[tex]\frac{28}{3}\text{ yards}=28\text{ feet}[/tex]

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.