Answer:
(3,2),(3,-2),(-3,2),(-3,-2)
Step-by-step explanation:
The given system of equations is
[tex]x^2+y^2=13...(i)\\\\x^2-y^2=5...(ii)[/tex]
Add equations (i) and (ii) is
[tex]2x^2=18[/tex]
Solve the equation for x. For this divide both sides by 2
[tex]x^2=9[/tex]
Take square root both sides
[tex]\sqrt{x^2}=\pm\sqrt9\\\\x=\pm3[/tex]
For x = 3, -3
[tex](\pm3)^2+y^2=13\\9+y^2=13\\y^2=4\\y=\pm2[/tex]
Therefore, the solutions are
(3,2),(3,-2),(-3,2),(-3,-2)
Therefore, all the points are the solutions of the system of equations.
