Answer:
Margin of error = 0.09
Confidence interval = (0.29, 0.41)
Step-by-step explanation:
Sample size, n = 1023
p = 38%
= 0.38
Standard deviation, σ = 1.5
Consider the level of confidence to be 95%
So, corresponding z* value for 95% confidence level = 1.96
[tex]\text{Now, Margin of error = }z^*\times \frac{\sigma}{\sqrt{n}}\\\\\text{Margin of error = }1.96\times \frac{1.5}{\sqrt{1023}}\\\\\textbf{Margin of error = }\bf 0.09[/tex]
Hence, confidence interval = p ± margin of error
= 0.38 ± 0.09
= (0.29, 0.47)
