Answer:The density of iron in [tex]0.0784 g/cm^3[/tex]
Explanation:
The density of the crystal solids is calculated by using :
[tex]\rho=\frac{Z\times M}{N_A\times a^3}[/tex]
Z = number of atoms in crystal lattice in body centered cubic cell = 2
M = Atomic mass = 55.85 g/mol
a = Edge length of the crystal = 287 pm = [tex]287\times 10^{-10}cm[/tex]
[tex]1 pm=1\times 1-^{-10} cm[/tex]
[tex]\rho=\frac{2\times 55.85 g/mol}{6.022\times 10^{23}\times (287\times 10^{-10}cm)^3}[/tex]
[tex]\rho=0.0784 g/cm^3[/tex]
The density of iron in [tex]0.0784 g/cm^3[/tex]
