Respuesta :
distance to the star Betelgeuse: 640 ly
As we know that
[tex]1 ly = 63000 AU[/tex]
also we know that
[tex]1AU = 1.5 \times 10^8 km[/tex]
[tex]1 ly = 63000 (1.5 \times 10^8) = 9.45 \times 10^{12} km[/tex]
So the distance of Betelgeuse = 640 ly
[tex]d_1 = 640 \times 9.45 \times 10^{12} = 6.05 \times 10^{15} m[/tex]
distance to the star VY Canis Majoris: [tex]3.09 × 10^8 AU[/tex]
[tex]d_2 = 3.09\times 10^8 \times 1.5 \times 10^8 km[/tex]
[tex]d_2 = 4.64 \times 10^{16} km[/tex]
distance to the galaxy Large Magellanic Cloud: 49976 pc
[tex]1 pc = 3.262 ly = 3.262 \times 9.45 \times 10^{12} km[/tex]
[tex]1pc = 3.08 \times 10^{13} km[/tex]
now we have
[tex]d_3 = 49976 \times 3.08 \times 10^{13}[/tex]
[tex]d_3 = 1.54 \times 10^{18} km[/tex]
distance to Neptune at the farthest: 4.7 billion km
[tex]d_4 = 4.7 \times 10^9 km[/tex]
now the order of distance from least to greatest is as following
1. distance to Neptune at the farthest
2. distance of Betelgeuse
3. distance to the star VY Canis Majoris
4. distance to the galaxy Large Magellanic Cloud
Answer:
1. distance to Neptune at the farthest2. distance of Betelgeuse3. distance to the star VY Canis Majoris4. distance to the galaxy Large Magellanic Cloud
Explanation:
