As ball is projected up in air at an angle of 45 degree without any air resistance
Let the initial speed will be v
now we will have
In x direction
[tex]v_x = v cos45[/tex]
in y direction
[tex]v_y = vsin45[/tex]
now displacement in x direction
[tex]x = (vcos45)t + 0[/tex]
displacement in y direction
[tex]y = (vsin45)t - \frac{1}{2}gt^2[/tex]
now from above two equations we have
[tex]y = (vsin45)\frac{x}{vcos45} - \frac{1}{2}g(\frac{x}{vcos45})^2[/tex]
[tex]y = xtan45 - \frac{1}{2v^2cos^245}gx^2[/tex]
so above equation is a quadratic equation and hence it will be a parabolic curve
so correct answer will be
C. parabolic curve.
