Answer:
8.597 g/cm³.
Explanation:
Density of Cu = 8.95 g/cm³,
% of Cu = 80.5 %,
Density of Zn = 7.14 g/cm³,
% of Zn = 19.5 %.
∴ The density of the alloy = [(density of Cu) (Cu % / 100) + (density of Zn) (Zn % / 100)] = [( 8.95 g/cm³) (80.5 / 100) + (7.14 g/cm³) (19.5 / 100) = [7.205 g/cm³ + 1.39 g/cm³] = 8.597 g/cm³.
Alloy is the combination of elements in which at least one of them is metal. The density of the copper and zinc alloy is [tex]\rm 8.597 g/cm^{3}.[/tex]
Density is the ratio of mass to volume of the substance and is given as the unit of gm per cubic centimetre.
Given,
The formula to calculate the density of the alloy is given as:
[tex]\text{The density of the alloy} = [(\text{density of Cu}) (\dfrac{\rm Cu \%}{100}) + (\text{density of Zn}) (\dfrac{\rm Zn \% }{ 100})][/tex]
Substituting values in the above equation:
[tex]\begin{aligned}&=[( 8.95\rm \; g/cm^{3}) (\rm \dfrac{80.5}{100}) + (7.14\;\rm g/cm^{3}) (\dfrac{19.5}{100}) \\\\&=[7.205 \;\rm g/cm^{3} + 1.39\;\rm g/cm^{3}]\\\\&= 8.597 \;\rm g/cm^{3}\end{aligned}[/tex]
Therefore, the density of the alloy is [tex]\rm 8.597 \; g/cm^{3}.[/tex]
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