The rate constant for a certain reaction is k = 5.50×10−3 s−1 . if the initial reactant concentration was 0.550 m, what will the concentration be after 2.00 minutes? express your answer with the a

Respuesta :

Answer: 0.19 m

Explanation:- Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

[tex]Rate=k[A]^x[/tex]    (1)

k= rate constant

x= order= 1

As the units of [tex]k=s^{−1}[/tex] , the reaction follows first order kinetics.

[tex]Rate= 5.50\times 10^{-3}\times [0.550]^1=0.003ms^{-1}[/tex]

Also rate is the change in concentration of reactants or products in a given time.

[tex]Rate=\frac{-d[A]}{dt}[/tex]        (2)

Equating (1) and (2)

[tex]Rate=\frac{-d[A]}{dt}=\frac{-[A_f-A_i]}{dt}=k[A][/tex]

[tex]0.003=-\frac{[A_f-0.550]}{120s}[/tex]

[tex]A_f=0.19m[/tex]

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