Respuesta :
The area of the square (24in×24in) is 576.
The area of the semi-circle is 226.08 [[(r=12, pi=3.14) (A= 1/2×(pi × r^2)], r=12, r^2=144, pi=3.14, 144×3.14=452.16÷2=226.08]
The total combined area of the banner is - 802.08 in
The area of the semi-circle is 226.08 [[(r=12, pi=3.14) (A= 1/2×(pi × r^2)], r=12, r^2=144, pi=3.14, 144×3.14=452.16÷2=226.08]
The total combined area of the banner is - 802.08 in
Answer:
The total area of the banner is 802.08 in².
Step-by-step explanation:
Separate the banner into simpler shapes as described in the problem: a square and a semicircle.
Find the area of the simpler figures.
Square
A = s2
A = 24 · 24
A = 576
The area of the square is 576 in2.
Semicircle
A = 1/ 2
πr2
A = 1/ 2
(3.14) (12)2
A = 1/ 2
(3.14) (144)
A = 226.08
The area of the semicircle is 226.08 in2.
Find the area of the banner.
A = 576 + 226.08
A = 802.08
The total area of the banner is 802.08 in².
