As we can see in the figure attached here
The velocity of aircraft is given as
[tex]v_p = 150 km/h[/tex] at 225 degree
velocity of wind is given as
[tex]v_a = 35 km/h[/tex] at 315 degree
so here the net velocity of aircraft will be the vector sum of aircraft speed and wind speed
since in the figure we can see that the two speeds are perpendicular to each other
so we can say that the resultant of two speed can be given by using Pythagoras theorem
so we will have
[tex]v_{net} = \sqrt{v_a^2 + v_p^2}[/tex]
[tex]v_{net} = \sqrt{150^2 + 35^2}[/tex]
[tex]v_{net} = 154 km/h[/tex]
so net speed of aircraft will be 154 km/h
The aircraft’s ground velocity is mathematically given as
V=154km/h
Question Parameters:
A small aircraft, on a heading of 225°, is cruising at 150 km/h. It is encountering a wind blowing from a bearing of 315° at 35 km/h.
Generally the equation using Pythagoras theorem of the resultant speed is mathematically given as
[tex]V=\sqrt{Va^2+Vp^2}[/tex]
Therefore
[tex]V=\sqrt{150^2+35^2}[/tex]
V=154km/h
Therefore,the aircraft’s ground velocity is
V=154km/h
For more information on Speed
https://brainly.com/question/17617636
