A student is working in a lab to determine how time affects impulse. The student keeps the force the same in each trial but changes the impact time. Some data is shown.
Answer:
Trail 3
Explanation:
As we know by Newton's II law that rate of change in momentum is always net force applied on the object.
Here we know that
[tex]F = \frac{\Delta P}{\Delta t}[/tex]
now we also know that change in momentum is known as impulse
so here impulse and force relation is given as
[tex]impulse = F\Delta t[/tex]
so here in order to find the greatest impulse we need to find the product of force and time to be the maximum as per above formula
so we have
trail 1
impulse = 500 (0.25) = 125 Ns
trial 2
impulse = 500(0.15) = 75 Ns
trial 3
impulse = 500(0.45) = 225 Ns
trial 4
impulse = 500(0.33) = 165 Ns
so out of the four trials maximum impulse is for trial 3