Answer:
[tex]\lim_{x \to 16} \frac{20+x}{20+x}[/tex] = 1
Step-by-step explanation:
We are given the expression, [tex]\lim_{x \to 16} \frac{20+x}{20+x}[/tex].
Since, we have that,
The numerator and denominator is (20+x), which is a polynomial is continuous for all the real numbers i.e. for all x belonging to [tex](-\infty,\infty)[/tex].
Thus, the limit exists and is given by,
[tex]\lim_{x \to 16} \frac{20+x}{20+x}[/tex] = [tex]\frac{20+16}{20+16}[/tex] = [tex]\frac{36}{36}[/tex] = 1.
So, [tex]\lim_{x \to 16} \frac{20+x}{20+x}[/tex] = 1.
