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Find the work w1 done on the block by the force of magnitude f1 = 65.0 n as the block moves from xi = -3.00 cm to xf = 3.00 cm .

Respuesta :

SFM19613
W = F•dx
F = 65 N,
dx = xf - xi = 0.03 m - (-0.03 m) = 0.06 m
W = 65 N × 0.06 m = 3.9 J
shubhamchouhanvrVT

The work done in displacing the object will be equal to 3.9 J

What is work?

When the force acts upon the system and it undergoes a change in its position , i.e., displacement occurs then displacement work is said to be done .

The formula used to calculate work is given as:

[tex]W=F\Delta D[/tex]

Here F=65 N and [tex]\Delta D=X_f-X_i=3-(-3)=6[/tex]

[tex]W=65\times 6=390 \ N-cm[/tex]

[tex]W=390\times 0.01=3.9 J[/tex]

Hence the work done in displacing the object will be equal to 3.9 J

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