[tex]x = \frac{1}{3}y + 2 \\ \\ x + 8 = \frac{1}{2}y[/tex]
We substitute for x in the second equation.
[tex] \frac{1}{3}y +2 + 8 = \frac{1}{2}y \\ \\ \frac{1}{3}y + 10 = \frac{1}{2}y[/tex]
We multiply both sides by 6:
2y + 60 = 3y
So y = 60 and x =
[tex] \frac{1}{3} \times 60 + 2 = 22[/tex]
