Answer
The correct answer is B
Explanation
The y-component of the vector is opposite to the given angle which is [tex]81\degree[/tex]. See diagram.
The hypotenuse, which is the magnitude of the vector is [tex]17[/tex] units.
The y-component of the vector can be found using the sine ratio.
Recall that the mnemonics for the sine ratio is SOH which means
[tex]\sin\theta=\frac{Opposite}{Hypotenuse}[/tex]
This implies that,
[tex]\sin81\degree=\frac{y}{17}[/tex]
We multiply both sides by 17 to get,
[tex]y=17\sin81\degree[/tex]
This gives us
[tex]y=17(0.9877)[/tex]
We evaluate to get,
[tex]y=16.79[/tex]
The y-component of the vector is [tex]16.8[/tex] to the nearest tenth.
