What is the length of the x-component of the vector shown below?
A. 5.6
B. 6.1
C. 13.9
D. 15
Answer:
The x-component is [tex]13.9[/tex]
Step-by-step explanation:
We can use the cosine ratio to find the x-component of the given vector.
Recall that,
[tex]\cos\theta=\frac{Adjacent}{hypotenuse}[/tex]
In our case the adjacent is the x-component and the hypotenuse is the magnitude of the vector which is 15 units.
This implies that,
[tex]\cos22\degree=\frac{x}{15}[/tex]
We solve for x to get,
[tex]x=15\cos22\degree[/tex]
This implies that,
[tex]x=15(0.92718)[/tex]
[tex]\therefore x=13.9[/tex] units
The correct answer is C