Answer:
8 sqrt(2) = h
Step-by-step explanation:
We know that is the two angle are equal, the two sides opposite them are equal (isosceles triangle) so both legs of the right triangle are 8
Then using the pythagorean theorem
a^2 + b^2 =c^2
where a and b are the legs (which are both 8 in this case) and c=h
8^2 + 8^2 = h^2
64+64 = h^2
128 = h^2
Take the square root of each side
sqrt(128) = sqrt(h^2)
We know that sqrt(ab) = sqrt(a) sqrt(b)
sqrt(2) sqrt(64) = h
8 sqrt(2) = h
