This is simple.
=[tex] 3\frac{3}{5} [/tex] ÷ [tex] 4\frac{1}{2} [/tex]
change the mixed fractions to improper ones.
[tex] \frac{18}{5} [/tex] ÷ [tex] \frac{9}{2} [/tex]
Multiply [tex] \frac{18}{5} [/tex] by the reciprocal of [tex] \frac{9}{2} [/tex] which is [tex] \frac{2}{9} [/tex]
=[tex] \frac{18}{5} [/tex] × [tex] \frac{2}{9} [/tex]
=[tex] \frac{36}{45} [/tex]
Since it can be simplified further, we get the answer
[tex] \frac{4}{5} [/tex]
How?
There is a common multiple 9
[tex] \frac{36/9}{45/9} [/tex]
=[tex] \frac{4}{5} [/tex]
Answer= B. [tex] \frac{4}{5} [/tex]
