Need help with two questions!!
Answer:
the slope of A is twice the slope of B
y =-2x -4
Step-by-step explanation:
function A = 6x-1
m=6
b=-1
Function B
(0,1) ( 1,4)
slope = (y2-y1)/(x2-x1)
= (4-1)/(1-0)
= 3/1
= 3
slope intercept form the y intercept is 1
y=mx+b
y = 3x+1
compare the slopes
ma = 6
mb = 3
ma is 2 times mb
(-2,0)
(0,-4)
slope = (y2-y1)/(x2-x1)
= (-4-0)/(0--2)
= (-4-0)/(0+2)
= -4/2
m=-2
the y intercept is -4
slope intercept form is y = mx+b
y =-2x -4
Couple things to note:
For the first problem, we know the slope of Function A is 6 (refer to slope-intercept form above). To compare the slopes of Function A and Function B, first find the slope of Function B.
Use y₁ - y₂ / x₁ - x₂. Two points on the line are (0, 1) and (-1, -2). Plug these into the formula accordingly and solve for slope.
y₁ - y₂ / x₁ - x₂
1 - (-2) / 0 - (-1)
1 + 2 / 0 + 1
3 / 1
3
The slope of Function B is 3. This is half of 6 (the slope of Function A), so the correct answer to question 1 is the first option: Slope of Function B = 2 × Slope of Function A.
For the second problem, substitute m and b in y = mx + b according to the graph. b is the y-intercept (the point at which the line intersects the y-axis); it is (0, -4), or -4. This gives us
y = mx - 4
We must now find m. Follow the same steps above to find slope. Our two points are (-2, 0) and (0, -4).
y₁ - y₂ / x₁ - x₂
0 - (-4) / -2 - 0
0 + 4 / -2
4 / -2
-2
Substitute.
y = -2x - 4
The first option is the correct answer.