Respuesta :
Replace with
1950
m
m
H
g
1950mmHg and simplify.
1.2
,
1950
m
m
H
g
,
15
,
500
m
L
Answer:
[tex]T=404.16K=13.1^oC[/tex]
Explanation:
Hello,
In this case, we use the ideal gas equation to compute the requested temperature as shown below and considering the proper units:
[tex]PV=nRT\\T=\frac{PV}{nR}=\frac{1950mmHg*\frac{1atm}{760mmHg}*15500mL*\frac{1L}{1000mL} }{1.2mol*0.082 \frac{atm*L}{mol*K} } \\T=404.16K=13.1^oC[/tex]
Best regards.