Mrs. Piper is driving Anna, Jo, and Mai home from school. All of them want to ride in the front seat. How can she make a fair decision about who rides in the front seat?
Answer:
option-B and option-A
Step-by-step explanation:
we will select each options and then we verify it
(A)
We know that when a die is rolled
There six possibilities
and two numbers are assigned to each
so, each are getting equal shares
so, this is fair
so, this is TRUE
(B)
There will be three names in three piece of paper
so, each having equal probability of getting front seat
so, this makes a fair decision
so, this is TRUE
(C)
We know that when a coin is flipped twice , we can get same face again and again
It won't make equal probability for each one
so, it won't be fair for anyone
so, this is FALSE
(D)
We know that when a die is rolled , we can get same number again and again
It won't make equal probability for each one
so, it won't be fair for anyone
so, this is FALSE
Answer:
A and B
Step-by-step explanation:
Randomly selecting the kid will be a fair decision.
A. True because all kids have the same percentage to win
The probability that Anna wins: 1/6 + 1/6 = 1/3
The probability that Jo wins: 1/6 + 1/6 = 1/3
The probability that Mai wins: 1/6 + 1/6 = 1/3
B. True because all kids have the same percentage to win
The probability that Anna wins: 1/3
The probability that Jo wins: 1/3
The probability that Mai wins: 1/3
D. Wrong. Because all kids do not have the same percentage to win
No matter what the result is in the 1st toss, Mai always have 100% chance to move to the second toss. While Jo and Anna only have 50% to go to the second toss.
D. Wrong. Because all kids do not have the same percentage to win
The probability that Anna wins: 1/6
The probability that Jo wins: 1/6
The probability that Mai wins: 4/6 = 2/3