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Find the equation of a parabola with vertex at the origin and focus (0, -32).
y^2= -128x
x^2= -32y
x^2= 128y
x^2=-128y

Respuesta :

Answer:

x^2 = -128y

Step-by-step explanation:

The general formula for this type of parabola is x^2 = 4ay  where a is  the y coordinate of the focus. So 4a = 4*-32 = 1-28.

So the answer is  x^2 = -128y

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