A survey question revealed that at a particular college 87 percent of students worked at least sometime during their undergraduate career and 13 percent did not work at all. Another question showed that 32 percent of the students worked throughout their undergraduate career. A pie chart is created that includes the category “Students who worked sometime during their undergraduate career, but not throughout.” What would the central angle be for this category?

A. 198 degrees
B. 47 degrees
C. 313 degrees
D. 115 degrees

Please give a straight answer! Thank you! :)

Respuesta :

The central angle be for this category is A. 198 degrees

Further explanation

The probability of an event is defined as the possibility of an event occurring against sample space.

[tex]\large { \boxed {P(A) = \frac{\text{Number of Favorable Outcomes to A}}{\text {Total Number of Outcomes}} } }[/tex]

Permutation ( Arrangement )

Permutation is the number of ways to arrange objects.

[tex]\large {\boxed {^nP_r = \frac{n!}{(n - r)!} } }[/tex]

Combination ( Selection )

Combination is the number of ways to select objects.

[tex]\large {\boxed {^nC_r = \frac{n!}{r! (n - r)!} } }[/tex]

Let us tackle the problem.

This problem is about Percentage.

32 percent of the students worked throughout their undergraduate career.

[tex]\texttt{Percentage of Students Worked throughout their undergraduate career} = 32 \%[/tex]

[tex]\texttt{ }[/tex]

A survey question revealed that at a particular college 87 percent of students worked at least sometime during their undergraduate career.

[tex]\texttt{Percentage of Students Worked sometime but not throughout} = 87 \% - 32 \%[/tex]

[tex]\texttt{Percentage of Students Worked sometime but not throughout} = 55 \%[/tex]

[tex]\texttt{ }[/tex]

Since the angle of 1 rotation is 360 degrees , then:

[tex]\texttt{Central Angle for this category} = 55 \% \times 360^o[/tex]

[tex]\texttt{Central Angle for this category} = \frac{55}{100} \times 360^o[/tex]

[tex]\texttt{Central Angle for this category} = \frac{11}{20} \times 360^o[/tex]

[tex]\texttt{Central Angle for this category} = 11 \times \frac{360^o}{20}[/tex]

[tex]\texttt{Central Angle for this category} = 11 \times 18^o[/tex]

[tex]\texttt{Central Angle for this category} = 198^o[/tex]

[tex]\texttt{ }[/tex]

Learn more

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Answer details

Grade: High School

Subject: Mathematics

Chapter: Probability

Keywords: Probability , Sample , Space , Six , Dice , Die , Binomial , Distribution , Mean , Variance , Standard Deviation

Ver imagen johanrusli

Answer: A. 198 degrees

Step-by-step explanation:

Given : The proportion of students worked at least sometime during their undergraduate career = 87%= 0.87

The proportion of the students worked throughout their undergraduate career= 32%=0.32

Now, the  proportion of the students who worked sometime during their undergraduate career, but not throughout. = 0.87- 0.32= 0.55

For pie chart the central angle would be  :-

[tex]\text{Proportion of required category}\times 360^{\circ}\\\\=0.55\times360^{\circ}\\\\=198^{\circ}[/tex]

Hence, the central angle be for this category = 198 degrees

Q&A Education