Answer: 0.429
Step-by-step explanation:
From the given table, the total number of games were loss = 12+16=28
The number of games was played by the wolves and was a loss = 12
The total number of games played  = 18+12+16+14=60
Now, the probability of games was played by the wolves and was a loss is given by ;-
[tex]\text{P(wolf and loss)}=\dfrac{12}{60}=\dfrac{1}{5}[/tex]
The probability of games that were loss is given by :-
[tex]\text{P(loss)}=\dfrac{28}{60}=\dfrac{7}{15}[/tex]
Now, the probability that a randomly selected game from the season was played by the wolves, given that it was a loss is given by :-
[tex]=\dfrac{\text{P(wolf and loss)}}{\text{P(loss)}}\\\\=\dfrac{\dfrac{1}{5}}{\dfrac{7}{15}}\\\\\\=\dfrac{3}{7}=0.428571428571\approx0.429[/tex]
