Respuesta :
Answer:
753.98 cubic cm.
Step-by-step explanation:
We have been given that from right circular cylinder with height 10 cm and radius of base 6 cm, a right circular cone of the same height and base is removed.
To find the area of remaining solid we will subtract volume of cone from volume of cylinder.
[tex]\text{Volume of remaining solid}=\text{Volume of cylinder- Volume of cone}[/tex]
[tex]\text{Volume of remaining solid}=\pi r^{2} h- \frac{1}{3}\pi r^{2}h[/tex]
[tex]\text{Volume of remaining solid}=\frac{3}{3}\pi r^{2} h- \frac{1}{3}\pi r^{2}h[/tex]
[tex]\text{Volume of remaining solid}=\frac{2}{3}\pi r^{2} h[/tex]
Upon substituting our given values in the formula we will get,
[tex]\text{Volume of remaining solid}=\frac{2}{3}\pi*6^{2}*10[/tex]
[tex]\text{Volume of remaining solid}=\frac{2}{3}\pi*36*10[/tex]
[tex]\text{Volume of remaining solid}=2*\pi*12*10[/tex]
[tex]\text{Volume of remaining solid}=240\pi[/tex]
[tex]\text{Volume of remaining solid}=753.9822368615503772\approx 753.98[/tex]
Therefore, the volume of remaining solid is 753.98 cubic cm.
