Respuesta :
Answer is:
1) orbital on C2 is sp2 hybrid orbitals and orbital on Cl is p atomic orbital.
Carbon atom is sp2 hybridized, it has three sp2 orbitals and one p orbital, they form four bonds. Three sp2 orbitals form three sigma bonds. Pi bonds are formed between two p orbitals on C1 and C2 atoms.
In sp2 hybridization the 2s orbital mixes with only two of the three available 2p orbitals.
2) the approximate C1-C2-Cl bond angle is 120°.
The orbital on C2 is [tex]\rm \bold{ sp_2}[/tex] while on Cl it p-orbital that form bond. The bond angle [tex]\rm\bold{C_1- C_2-Cl}[/tex] is [tex]\rm \bold{ 120^\cdot}[/tex].
[tex]\rm \bold{ sp_2}[/tex] Hybridization:
- The 2s orbital hybridizes with only two of the three available 2p orbitals.
- The bond angle is [tex]\rm \bold{ 120^\cdot}[/tex]. Three [tex]\rm \bold{ sp_2}[/tex] orbitals form three [tex]\sigma[/tex]-bonds.
- [tex]\pi[/tex]-bonds are formed between two p-orbitals on C1 and C2 atoms.
Hence, we can conclude that the orbital on C2 is [tex]\rm \bold{ sp_2}[/tex] while on Cl it p-orbital that form bond. The bond angle [tex]\rm\bold{C_1- C_2-Cl}[/tex] is [tex]\rm \bold{ 120^\cdot}[/tex].
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