The points form the given equations are(-2,-4) & (4,8).
We have given that,
y=-2x.....(1)
y=x^2-8........(2)
We solve this system by using the substitution method.
The substitution method is a simple way to solve linear equations algebraically and find the solutions to the variables. As the name suggests, it involves finding the value of the x-variable in terms of the y-variable and then substituting or replacing the value of the x-variable in the second equation.
Therefore we have
use the value of y in the second equation
-2x=x^2-8
x^2+2z-8=0
(x-2)(x-4)=0
x+2=0,x-4=0
x=-2,x=4
Use this value of x in equation so we get,
y=-2 and y=8
Therefore the points form the given equations are(-2,-4) & (4,8).
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