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Answer:
Average number of jumps on lowest bar = 3/2 = 1.5
Average number of jumps on middle bar = 6/4 = 1.5
Average number of jumps on highest bar = 4/1 = 4
Overall average number of jumps = 3/2 + 6/4 + 4/1 = 7
Overall average number of jumps = 1/probability of complete the lowest bar +1/probability of complete the middle bar + 1/probability of complete the highest bar
Equations of Shane’s overall average number of jumps completed = x * (7/13), where x is the total number of overall jumps
Average jumps on lowest bar = 3/2 = 1.5
Average jumps on middle bar = 6/4 = 1.5
Average jumps on highest bar = 4/1 = 4
Overall average jumps = 3/2 + 6/4 + 4/1 = 7
Overall average number of jumps = 1/probability of complete the lowest bar +1/probability of complete the middle bar + 1/probability of complete the highest bar
Shane’s number of jumps = x * (7/13),
Shane’s number of jumps=7
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