Answer : The molarity of solution is, 0.878 mole/L
Solution : Given,
Mass of [tex]MgCl_2[/tex] = 8.36 g
Volume of solution = 500 ml
Molar mass of [tex]MgCl_2[/tex] = 95.2 g/mole
Molarity : It is defined as the number of moles of solute present in one liter of solution.
Formula used :
[tex]Molarity=\frac{w\times 1000}{M\times V_s}[/tex]
where,
w = mass of [tex]MgCl_2[/tex] (solute)
M = molar mass of [tex]MgCl_2[/tex]
[tex]V_s[/tex] = volume of solution in liter
Now put all the given values in this formula, we get the molarity of a solution.
[tex]Molarity=\frac{(8.36g)\times 1000}{(95.2g/mole)\times (500L)}[/tex]
[tex]Molarity=0.878mole/L[/tex]
Therefore, the molarity of solution is, 0.878 mole/L
