Answer:
let u be x^(1/3)
x^(2/3) = [tex](x^{1/3})^{2}[/tex] = u^2
x^(2/3) + 5x^(1/3) - 6= 0
u^(2) + 5u - 6 = 0
u=1 or u = -6
u=x^(1/3)
then x = 1 or x = -216
Step-by-step explanation:
