Respuesta :
Answer:
16.6 degrees
Explanation:
We can solve the problem by using Snell's law for refraction:
[tex]n_1 sin \theta_1 = n_2 sin \theta_2[/tex]
where:
[tex]n_1 = 1.00[/tex] is the index of refraction of the first medium (air)
[tex]\theta_1 = 24.8^{\circ}[/tex] is the angle of incidence
[tex]n_2 = 1.472[/tex] is the index of refraction of the second medium (turpentine)
[tex]\theta_2[/tex] is the angle of refraction of light in turpentine
By re-arranging the equation and using the numbers, we find
[tex]sin \theta_2 = \frac{n_1}{n_2} sin \theta_i = \frac{1.0}{1.472} sin 24.8^{\circ}=0.285\\\theta_2 = sin^{-1} (0.285)=16.6^{\circ}[/tex]
The angle of refraction of the light in turpentine will be [tex]\boxed{38.1^\circ}[/tex].
Explanation:
Given:
The refractive index of the turpentine is[tex]1.472[/tex].
The refractive index of the water is [tex]1.333[/tex].
The angle that the light makes with the surface of the turpentine is [tex]24.8^\circ[/tex].
Concept:
As the light is incident on the surface of the turpentine at the air-turpentine interface, the light gets refracted from the surface. The refraction of light occurs due to change in the refractive index at the air-turpentine surface.
The angle of the refracted ray after undergoing refraction is given by the Snell's law.
[tex]\boxed{n_1sin\,i=n_2sin\,r}[/tex]
Here, [tex]n_1[/tex] is the refractive index of first medium, [tex]n_2[/tex] is the refractive index of second medium, [tex]i[/tex] is the angle of incidence and [tex]r[/tex] is the angle of refraction.
The angle of incidence is the angle made by the light from the normal to the surface. So, in this case, the angle of incidence will be [tex](90^\circ-24.8^\circ)[/tex] i.e. [tex]65.2^\circ[/tex].
Substitute the values in above expression.
[tex]\begin{aligned}(1)sin\,(65.2^\circ)&=(1.472)sin\,(r)\\r&=sin^{-1}\left(\dfrac{1}{1.472}sin\,(65.2^\circ)\right)\\&=sin^{-1}(0.616)\\&\approx38.1^\circ\end{aligned}[/tex]
Thus, The angle of refraction of the light in turpentine will be [tex]\boxed{38.1^\circ}[/tex].
Learn More:
1. How does the reflection differ from refraction and diffraction https://brainly.com/question/3183125
2. The reason for the refraction of light at air water interface https://brainly.com/question/3095091
3. Approximate length of the unsharpened pencil https://brainly.com/question/6140057
Answer Details:
Grade: High School
Subject: Physics
Chapter: Refraction
Keywords:
thin layer, turpentine, Snell's law, refraction, air, interface, normal, incident, light, refracted, refraction, refraction angle.
