Answer:
B (√6)/4
Step-by-step explanation:
The smallest multiplier that will make the denominator of the fraction into a perfect square is 2, so you have ...
[tex]\displaystyle\sqrt{\frac{3}{8}}=\sqrt{\frac{3\cdot 2}{8\cdot 2}}\\\\=\sqrt{\frac{6}{16}}=\frac{\sqrt{6}}{\sqrt{16}}\\\\=\frac{\sqrt{6}}{4}[/tex]
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Answer choice D is also a correct rationalization of the denominator, but is not simplified as far as it can be. √24 = 2√6, so a factor of 2 can be cancelled from numerator and denominator, giving answer choice B.
